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Hydraulic Pressure Drop & Power Calculator

Last updated: 31 Jul 2025 | Author: Brij | Review By: Irshad
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Use our Hydraulic Pressure Drop & Power Calculator to compute flow velocity, pressure drop, and required pump power from flow rate, pipe diameter, and friction factor.

Hydraulic Results

The Hydraulic Pressure Drop & Power Calculator helps determine the pressure losses in a fluid system and calculates the power required to overcome these losses. It uses the Darcy-Weisbach equation, which is widely accepted in fluid dynamics for calculating pressure drop due to friction in pipes.

Formulas Used

1. Flow Velocity (V)

The flow velocity is determined by dividing the volumetric flow rate by the cross-sectional area of the pipe:

V=QAV = \frac{Q}{A}V=AQ​

Where:

  • VVV = Flow velocity (m/s)
  • QQQ = Flow rate (m³/s)
  • AAA = Cross-sectional area of the pipe (m²)

2. Cross-Sectional Area of Pipe (A)

A=π(D2)2A = \pi \left( \frac{D}{2} \right)^2A=π(2D​)2

Where:

  • DDD = Pipe diameter (m)

3. Pressure Drop (ΔP\Delta PΔP)

Using the Darcy-Weisbach equation:

ΔP=f⋅LD⋅ρV22\Delta P = f \cdot \frac{L}{D} \cdot \frac{\rho V^2}{2}ΔP=f⋅DL​⋅2ρV2​

Where:

  • ΔP\Delta PΔP = Pressure drop (Pa)
  • fff = Friction factor (Darcy)
  • LLL = Pipe length (m)
  • DDD = Pipe diameter (m)
  • ρ\rhoρ = Fluid density (kg/m³)
  • VVV = Flow velocity (m/s)


4. Pump Power (P)

P=Q⋅ΔPP = Q \cdot \Delta PP=Q⋅ΔP

Where:

  • PPP = Power (W)
  • QQQ = Flow rate (m³/s)
  • ΔP\Delta PΔP = Pressure drop (Pa)

Example Calculation

Given:

  • Flow rate QQQ = 10 GPM10 \, \text{GPM}10GPM
  • Pipe diameter DDD = 2 in2 \, \text{in}2in
  • Pipe length LLL = 100 ft100 \, \text{ft}100ft
  • Fluid density ρρρ = 1000 kg/m31000 \, \text{kg/m}^31000kg/m3
  • Friction factor f ff = 0.02

Step 1: Convert Units

  • 10 GPM = 0.000631 m3/s0.000631 \, \text{m}^3/\text{s}0.000631m3/s
  • 2 in=0.0508 m\text{in} = 0.0508 \, \text{m}in=0.0508m
  • 100 ft=30.48 m\text{ft} = 30.48 \, \text{m}ft=30.48m

Step 2: Calculate Area

A=π(0.05082)2=0.002026 m2A = \pi \left( \frac{0.0508}{2} \right)^2 = 0.002026 \, m^2A=π(20.0508​)2=0.002026m2

Step 3: Calculate Velocity

V=0.0006310.002026=0.311 m/sV = \frac{0.000631}{0.002026} = 0.311 \, m/sV=0.0020260.000631​=0.311m/s

Step 4: Calculate Pressure Drop

ΔP=0.02⋅30.480.0508⋅1000⋅0.31122=588.4 Pa\Delta P = 0.02 \cdot \frac{30.48}{0.0508} \cdot \frac{1000 \cdot 0.311^2}{2} = 588.4 \, PaΔP=0.02⋅0.050830.48​⋅21000⋅0.3112​=588.4Pa

Step 5: Calculate Power

P=0.000631⋅588.4=0.371 WP = 0.000631 \cdot 588.4 = 0.371 \, WP=0.000631⋅588.4=0.371W


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